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 * geqo_eval.c
 *      Routines to evaluate query trees
 * Portions Copyright (c) 1996-2009, PostgreSQL Global Development Group
 * Portions Copyright (c) 1994, Regents of the University of California
 * $PostgreSQL: pgsql/src/backend/optimizer/geqo/geqo_eval.c,v 1.88 2009/01/01 17:23:43 momjian Exp $

/* contributed by:
   *  Martin Utesch                        * Institute of Automatic Control      *
   =                                       = University of Mining and Technology =
   *  utesch@aut.tu-freiberg.de  * Freiberg, Germany                       *

#include "postgres.h"

#include <float.h>
#include <limits.h>
#include <math.h>

#include "optimizer/geqo.h"
#include "optimizer/joininfo.h"
#include "optimizer/pathnode.h"
#include "optimizer/paths.h"
#include "utils/memutils.h"

static bool desirable_join(PlannerInfo *root,
                     RelOptInfo *outer_rel, RelOptInfo *inner_rel);

 * geqo_eval
 * Returns cost of a query tree as an individual of the population.
geqo_eval(Gene *tour, int num_gene, GeqoEvalData *evaldata)
      MemoryContext mycontext;
      MemoryContext oldcxt;
      RelOptInfo *joinrel;
      Cost        fitness;
      int               savelength;
      struct HTAB *savehash;

       * Because gimme_tree considers both left- and right-sided trees, there is
       * no difference between a tour (a,b,c,d,...) and a tour (b,a,c,d,...) ---
       * the same join orders will be considered. To avoid redundant cost
       * calculations, we simply reject tours where tour[0] > tour[1], assigning
       * them an artificially bad fitness.
       * init_tour() is aware of this rule and so we should never reject a tour
       * during the initial filling of the pool.      It seems difficult to persuade
       * the recombination logic never to break the rule, however.
      if (num_gene >= 2 && tour[0] > tour[1])
            return DBL_MAX;

       * Create a private memory context that will hold all temp storage
       * allocated inside gimme_tree().
       * Since geqo_eval() will be called many times, we can't afford to let all
       * that memory go unreclaimed until end of statement.  Note we make the
       * temp context a child of the planner's normal context, so that it will
       * be freed even if we abort via ereport(ERROR).
      mycontext = AllocSetContextCreate(CurrentMemoryContext,
      oldcxt = MemoryContextSwitchTo(mycontext);

       * gimme_tree will add entries to root->join_rel_list, which may or may
       * not already contain some entries.  The newly added entries will be
       * recycled by the MemoryContextDelete below, so we must ensure that the
       * list is restored to its former state before exiting.  We can do this by
       * truncating the list to its original length.  NOTE this assumes that any
       * added entries are appended at the end!
       * We also must take care not to mess up the outer join_rel_hash, if there
       * is one.  We can do this by just temporarily setting the link to NULL.
       * (If we are dealing with enough join rels, which we very likely are, a
       * new hash table will get built and used locally.)
      savelength = list_length(evaldata->root->join_rel_list);
      savehash = evaldata->root->join_rel_hash;

      evaldata->root->join_rel_hash = NULL;

      /* construct the best path for the given combination of relations */
      joinrel = gimme_tree(tour, num_gene, evaldata);

       * compute fitness
       * XXX geqo does not currently support optimization for partial result
       * retrieval --- how to fix?
      if (joinrel)
            fitness = joinrel->cheapest_total_path->total_cost;
            fitness = DBL_MAX;

       * Restore join_rel_list to its former state, and put back original
       * hashtable if any.
      evaldata->root->join_rel_list = list_truncate(evaldata->root->join_rel_list,
      evaldata->root->join_rel_hash = savehash;

      /* release all the memory acquired within gimme_tree */

      return fitness;

 * gimme_tree
 *      Form planner estimates for a join tree constructed in the specified
 *      order.
 *     'tour' is the proposed join order, of length 'num_gene'
 *     'evaldata' contains the context we need
 * Returns a new join relation whose cheapest path is the best plan for
 * this join order.  NB: will return NULL if join order is invalid.
 * The original implementation of this routine always joined in the specified
 * order, and so could only build left-sided plans (and right-sided and
 * mixtures, as a byproduct of the fact that make_join_rel() is symmetric).
 * It could never produce a "bushy" plan.  This had a couple of big problems,
 * of which the worst was that as of 7.4, there are situations involving IN
 * subqueries where the only valid plans are bushy.
 * The present implementation takes the given tour as a guideline, but
 * postpones joins that seem unsuitable according to some heuristic rules.
 * This allows correct bushy plans to be generated at need, and as a nice
 * side-effect it seems to materially improve the quality of the generated
 * plans.
RelOptInfo *
gimme_tree(Gene *tour, int num_gene, GeqoEvalData *evaldata)
      RelOptInfo **stack;
      int               stack_depth;
      RelOptInfo *joinrel;
      int               rel_count;

       * Create a stack to hold not-yet-joined relations.
      stack = (RelOptInfo **) palloc(num_gene * sizeof(RelOptInfo *));
      stack_depth = 0;

       * Push each relation onto the stack in the specified order.  After
       * pushing each relation, see whether the top two stack entries are
       * joinable according to the desirable_join() heuristics.  If so, join
       * them into one stack entry, and try again to combine with the next stack
       * entry down (if any).  When the stack top is no longer joinable,
       * continue to the next input relation.  After we have pushed the last
       * input relation, the heuristics are disabled and we force joining all
       * the remaining stack entries.
       * If desirable_join() always returns true, this produces a straight
       * left-to-right join just like the old code.  Otherwise we may produce a
       * bushy plan or a left/right-sided plan that really corresponds to some
       * tour other than the one given.  To the extent that the heuristics are
       * helpful, however, this will be a better plan than the raw tour.
       * Also, when a join attempt fails (because of OJ or IN constraints), we
       * may be able to recover and produce a workable plan, where the old code
       * just had to give up.  This case acts the same as a false result from
       * desirable_join().
      for (rel_count = 0; rel_count < num_gene; rel_count++)
            int               cur_rel_index;

            /* Get the next input relation and push it */
            cur_rel_index = (int) tour[rel_count];
            stack[stack_depth] = (RelOptInfo *) list_nth(evaldata->initial_rels,
                                                                               cur_rel_index - 1);

             * While it's feasible, pop the top two stack entries and replace with
             * their join.
            while (stack_depth >= 2)
                  RelOptInfo *outer_rel = stack[stack_depth - 2];
                  RelOptInfo *inner_rel = stack[stack_depth - 1];

                   * Don't pop if heuristics say not to join now.  However, once we
                   * have exhausted the input, the heuristics can't prevent popping.
                  if (rel_count < num_gene - 1 &&
                        !desirable_join(evaldata->root, outer_rel, inner_rel))

                   * Construct a RelOptInfo representing the join of these two input
                   * relations.  Note that we expect the joinrel not to exist in
                   * root->join_rel_list yet, and so the paths constructed for it
                   * will only include the ones we want.
                  joinrel = make_join_rel(evaldata->root, outer_rel, inner_rel);

                  /* Can't pop stack here if join order is not valid */
                  if (!joinrel)

                  /* Find and save the cheapest paths for this rel */

                  /* Pop the stack and replace the inputs with their join */
                  stack[stack_depth - 1] = joinrel;

      /* Did we succeed in forming a single join relation? */
      if (stack_depth == 1)
            joinrel = stack[0];
            joinrel = NULL;


      return joinrel;

 * Heuristics for gimme_tree: do we want to join these two relations?
static bool
desirable_join(PlannerInfo *root,
                     RelOptInfo *outer_rel, RelOptInfo *inner_rel)
       * Join if there is an applicable join clause, or if there is a join order
       * restriction forcing these rels to be joined.
      if (have_relevant_joinclause(root, outer_rel, inner_rel) ||
            have_join_order_restriction(root, outer_rel, inner_rel))
            return true;

      /* Otherwise postpone the join till later. */
      return false;

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